1、∵CD∥AB∴∠ECD=∠EFA（两直线平行,内错角相等）∠DEC=∠AEF（对顶角相等）又ED=EA∴△DEC≌△AEF∴DC=AF而DC=AB∴AB=AF2、由上面△DEC≌△AEF 得EC=EF又AB=AF（已证）BC=2AB（已知）∴BC=BF∴BE平分∠FBC（等腰...