如果a+(根号下a²-6a+9)=3成立,那么实数a的取值范围是多少
人气:167 ℃ 时间:2020-03-23 15:01:29
解答
a+√(a²-6a+9)=3
√[(a-3)²]=3-a
∴3-a≥0,
∴a≤3
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