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化简(2cos40度-cos20度)/sin20度
人气:144 ℃ 时间:2020-06-15 16:33:28
解答
(2cos40度-cos20度)/sin20度
=(cos40°+cos40°-cos20°)/sin20°
=(cos40°+cos(30°+10°)-cos(30°-10°))/sin20°
=(cos40°-2sin30°sin10°)/sin20°
=(cos40°-sin10°)/sin20°
=(sin50°-sin10°)/sin20°
=(sin(30°+20°)-sin(30°-20°))/sin20°
=2cos30°sin20°/sin20°
=2cos30°
=√3
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