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(2cos10°-sin20°)/cos20°化简求值
人气:336 ℃ 时间:2020-02-03 23:28:53
解答
=[2cos(30-20)-sin20]/cos20
=(2cos30cos20+2sin30sin20-sin20]/cos20
=(2*根号3/2*cos20+2*1/2sin20-sin20)/cos20
=(根号3cos20+sin20-sin20)/cos20
=根号3cos20/cos20
=根号3
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