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化简cos^4(a/2)-sin^4(a/2)
人气:231 ℃ 时间:2020-05-22 20:44:01
解答
[cos(a/2)]^4-[sin(a/2)]^4
={[cos(a/2)]^2+[sin(a/2)]^2}×{[cos(a/2)]^2-[sin(a/2)]^2}
=1×{[cos(a/2)]^2-[sin(a/2)]^2}
=cos[2×(a/2)]
=cosa
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