∫(1/(y-y^2))dy 等于多少?怎么算?_数学解答

∫(1/(y-y^2))dy 等于多少?怎么算?

人气：137 ℃　时间：2020-05-15 22:39:52

解答

答：
∫1/(y-y^2)dy
=∫{1/[y(1-y)]}dy
=∫[1/y+1/(1-y)]dy
=∫1/ydy+∫1/(1-y)dy
=In│y│-In│1-y│+C
=In│y/(1-y)│+C
C为常数.