f(x)=(1/3)^xg(x)与f(x)关于直线y=1对称；求g(x)设P(x,y)是g(x)图象上任一点,关于直线y=1的对称点P'(x',y'){x=x'{y+y'=2==>{x'=x{y'=2-yP'(x,2-y)P'点在f(x)图象上,所以2-y=(1/3)^xy=2-(1/3)^xg(x)=2-(1/3)^x...