函数y=3-2sin (3x+π/3)的值域为
人气:333 ℃ 时间:2020-03-31 17:22:25
解答
sin (3x+π/3)的值域为[-1,1]
-2sin (3x+π/3)值域是[-2,2]
所以y的值域是[1,5]
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