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已知x2-x-1=0,则-x3+2x2+2005的值为______.
人气:364 ℃ 时间:2020-10-01 21:28:22
解答
∵x2-x-1=0,
∴x2-x=1,
∴-x3+2x2+2005,
=-x(x2-x)+x2+2005,
=-x+x2+2005,
=2006.
故答案为:2006.
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