F(X)=2sin x cosx-2sinx的平方=sin2x-(1-cos2x)=sin2x+cos2x-1=√2sin(2x+π/4)-1所以①周期=2π÷2=π②x∈【π/24.π/4】2x+π/4∈【π/3,3π/4】x=π/4时取最小值=√2×√2/2-1=0x=π/8时取最大值=√2sin(2×π/8...