如果a与2b互为倒数,-c与d除以2互为相反数,|x|=3,2ab-2c+d+x除以3的值=?
2ab=1 2(-c+d/2)=0 x=3 x=-3
x=3
2ab-2c+d+x/3=4/3
x=-3
2ab-2c+d+x/3=-2/3