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已知3x2+4x-7=0,则6x4+11x3-7x2-3x-7=______.
人气:261 ℃ 时间:2019-08-19 12:54:23
解答
∵6x4+11x3-7x2-3x-7,
=6x4+8x3-14x2+3x3+4x2-7x+3x2+4x-7,
=2x2(3x2+4x-7)+x(3x2+4x-7)+(3x2+4x-7),
=(3x2+4x-7)(2x2+x+1),
又3x2+4x-7=0,
∴原式=0.
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