1.过抛物线的顶点O做两条互相垂直的弦OA和OB.求证：弦AB与抛物的对称轴相交于定点 2.过抛物线y2=2px（p
＞0)的焦点F作倾斜角为45°的直线,交抛物线于A、B两点,点A在x轴的上方,求AF绝对值比BF绝对值?
人气：358 ℃ 时间：2019-11-23 14:17:43
解答
y²=2px假设OA,OB斜率是k和-1/k则OA是y=kxOB是y=-x/k代入y²=2pxk²x²=2px,A不是原点x≠0x=2p/k²A(2p/k²,2p/k)同理,B(2pk²,-2pk)由两点式(y-2p/k)/(-2pk-2p/k)=(x-2p/k²)/(2pk...
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