> 数学 >
计算题.
(1)
2
x−1
+
x+1
1−x

(2)
x+3
3−x
+
x2−9
x2+6x+9

(3)a+2-
4
2−a
人气:283 ℃ 时间:2020-09-30 03:50:12
解答
(1)原式=
2
x−1
x+1
x−1
=
1−x
x−1
=-1;
(2)原式=
x+3
3−x
+
(x+3)(x−3)
(x+3)2
=
x−3
x+3
x+3
x−3
=
(x−3)2−(x+3)2
(x+3)(x−3)
=
12x
x2−9

(3)原式=
a+2
1
+
4
a−2
=
(a+2)(a−2)+4
a−2
=
a2
a−2
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