∴b2=ac-----------------------(2分)
∵B=60°
∴cosB=
a2+c2−b2 |
2ac |
1 |
2 |
联立方程组
|
解得a=b=c=
| ||
2 |
(Ⅱ)cosB=
a2+c2−b2 |
2ac |
a2+c2−ac |
2ac |
∵a2+c2≥2ac,∴cosB=
a2+c2−ac |
2ac |
2ac−ac |
2ac |
1 |
2 |
∴0°<B≤60°-----------------------(12分)
3 |
a2+c2−b2 |
2ac |
1 |
2 |
|
| ||
2 |
a2+c2−b2 |
2ac |
a2+c2−ac |
2ac |
a2+c2−ac |
2ac |
2ac−ac |
2ac |
1 |
2 |