(x)=√3sin2wx+2cos²wx =√3sin2wx+(2cos²wx-1)+1 =√3sin2wx+cos2wx+1 =2(√3/2sin2wx+1/2cos2wx)+1 =2(sin2wxcosπ/6+cos2wxsinπ/6)+1 =2sin(2wx+π/6)+1∵T=2π/2w=π∴w=1
x∈[0.π/2]∴2x+π/6∈[π/6,7π/6]∴sin(2x+π/6)∈[-1/2,1]∴f(x)∈[0,3]
f(X)=2sin2x向左移π/6