x+3

x2−1

÷

x2+6x+9

x2−2x+1

+

1

x+1

=

x+3

(x+1)(x−1)

•

(x−1)2

(x+3)2

+

1

x+1

=

1

x+1

•

x−1

x+3

+

1

x+1

=

1

x+1

(

x−1

x+3

+1)
=

1

x+1

•

2(x+1)

x+3

=

2

x+3

，
∵x²-1≠0，x+3≠0，x-1≠0，x+1≠0，
∴取x=2，
代入得：原式=

2

2+3

=

2

5

．