1y=(1/3)^x+ln(3x)y'=ln(1/3) *(1/3)^x +3*(1/3x)2y=(1-√x)(1+1/√x)=(1-x)/√x=1/√x-√x √x=x^(1/2)y'=(-1/2)*(1/√x^3)-(1/2)(1/√x)3y=cos2x/(sinx+cosx)=cosx-sinxy'=-sinx-cosx