> 数学 >
"表示度.sin(65"-x)cos(x-20")+cos(65"-x)cos(110"-x)
人气:490 ℃ 时间:2020-05-19 05:21:54
解答
sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)
=(1/2)[sin45°+sin(85°-2x)+cos(175°-2x)+cos45°]
=(1/2)[sin(85°-2x)-sin(85°-2x)+√2]
=√2/2.
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版