∠MBA=2∠MAB,设：M(x,y)1、若∠MBA=90°,此时M(2,3)2、若∠MBA≠90°,设直线MA的斜率是k1=tan∠MAB=y/(x＋1),直线MB的斜率是k2=tan(180°－∠MBA)=y/(x－2)则：∠MBA=2∠MABtan∠MBA=tan(2∠MAB)tan∠MBA=[2tan∠MA...你化简-y/(x-2)=[2y/(x+1)]/[1-y^2/(x+1)^2] 化简错了吧，我化简得3x^2-y^2-3=0 感谢你的解答！化简，得：2(x＋1)(x－2)＋(x＋1)²－y²=03x²－y²－3=0即：x²－y²/3=1