设矩阵p为 1,0,0 0,1,0 0,0,2 矩阵A为 2,0,0 0,-1,0 0,0,3 则（p^-1Ap）^100=?_数学解答

设矩阵p为 1,0,0 0,1,0 0,0,2 矩阵A为 2,0,0 0,-1,0 0,0,3 则（p^-1Ap）^100=?

人气：399 ℃　时间：2020-03-18 13:48:28

解答

(P^-1AP)^100
= P^-1 A^100 P
= diag(1,1,1/2) diag(2^100,1,3^100) diag(1,1,2)
= diag (2^100,1,3^100).