已知抛物线y=-2x2+bx+c的顶点坐标为(1,2),求b,c的值,并写出函数的解析式.
人气:131 ℃ 时间:2019-08-20 13:45:42
解答
∵抛物线y=-2x
2+bx+c的顶点坐标为(1,2),
∴-
=1,
解得b=4,
当x=1时,-2+4+c=2,
解得c=0,
所以,函数解析式为y=-2x
2+4x.
推荐
猜你喜欢
- 1、一个正方体棱长3分米,这个正方体棱长之和是()dm,它的表面积是()dm2,体积是()dm3.
- “嫦娥一号”遨游太空,让全体中国人的心随着它跳动了五天五夜,也让全世界...
- Everyone says the nurse is very______.She often helps the____people.A.kindly;sick B.kind;sickly
- 的文言现象(通假字,一词多义,词类活用,特殊句式)
- 从 爱亲者,不敢恶于人;敬亲者,不敢慢于人.这句话让我想到了孟子的名言:
- What do they think of Anna?改同义句
- 英语选择题,要说明选择理由
- His grandfather are not used to the city life_______ they used to live in a different country life.