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sin^2(θ)+4cosθ/sin(90-θ) -1/tan(90-θ)
人气:344 ℃ 时间:2020-07-04 11:28:03
解答
[sin^2(θ)+4cosθ]/sin(90-θ)-1/tan(90-θ)
=[sin^2(θ)+4cosθ]/cos(θ)-1/cotθ
=[sin^2(θ)+4cosθ]/cos(θ)-sin(θ)/cosθ
=[sin^2(θ)-sinθ+4cosθ]/cosθ
={sin(θ)[sin(θ)-1]+4cosθ]/cosθ
=tanθ(sinθ-1)+4
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