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化简求值 (a-b)/(a+2b)除以(a²-b²)/(a²+4ab+4b²)-1
人气:133 ℃ 时间:2020-03-19 18:21:03
解答
(a-b)/(a+2b)除以(a²-b²)/(a²+4ab+4b²)-1
=(a-b)/(a+2b)乘以(a²+4ab+4b²)/(a²-b²)-1
=(a+2b)/(a+b)-1
=b/(a+b)a=-2 b=-1 求值a=-2 b=-1 b/(a+b) =1/3
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