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设tanA=1,3sinB=sin(2A+B),求tan(2A+2B)的值
人气:281 ℃ 时间:2020-02-05 13:40:23
解答
tanA=1,得A=kπ+π/4,k属于z,3sinB=sin(2A+B)=sin2AcosB+cos2AsinB,两边同除cosB,得3tanB=sin2A+cos2AtanB2A=2kπ+π/2,k属于zsin2A=1,cos2A=0 代入,得3tanB=1,tanB=1/3 tan(A+B)=(tanA+tanB)/(1-tanAtanB...
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