当P的绝对值小于等于2时,不等式2X-1大于P（X^2—1）恒成立,求X的取值范围
人气：110 ℃ 时间：2019-12-20 13:21:37
解答
2x-1>P(x^2-1)
设：f(P)=P(x^2-1)-(2x-1)
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