函数f（x）=1/(4^x+m) (m>0),x1,x2属于R,当x1+x2=1时,f(x1)+f(x2)=1/2,求m的值
(2)已知数列{an}满足an=f(0)+f(1/n)+f(2/n)+……+f[(n-1)/n]+f(1),求an
“=[f(0/2k)+f(2k/2k)]+[f(1/2k)+f((2k-1)/2k)]+ … +[f((k-1)/2k)+f((k+1)/2k)]+f(k/2k)
=1/2+1/2+ … +1/2+f(1/2) ………… 有k个1/2 ”