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计算i-2根号3/(1+2根号3i)+(5+i^19)-(1+i/根号2)^22
人气:216 ℃ 时间:2020-07-10 23:02:37
解答
i-2√3/(1+2√3i)+(5+i^19)-(1+i/√2)^2=i-(2√3)(1-2√3i)/13+5-i-(1+i-1/4)
=i-(2√3/13-12i/13)+5-i-3/4-i=17/4-2√3/13-(1/13)i
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