1 (log4 3+log8 3)log3 2 =(lg3/lg4+lg3/lg8)*(lg2/lg3)=lg3*(1/lg4+1/lg8)*(lg2/lg3)=(1/lg4+1/lg8)*lg2=lg2/lg4+lg2/lg8=lg2/(2*lg2)+lg2/(3*lg2)=1/2+1/3=5/62 loga b×logb c×logc a=(lgb/lga)*(lgc/lgb)*(lga/...