函数子=2sin^2x +2sinx-3的值域是 答案多少教我下谢谢
人气：409 ℃ 时间：2020-02-22 05:59:22
解答
解答如下：
令t = sinx ∈[-1,1]
所以y = 2t² + 2t - 3
对称轴为直线t = -1/2
所以最小值在t = -1/2上取到,为-3.5
最大值在t = 1上取到,为1
所以值域为[-3.5,1]
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