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如图 三角形ABC中,角1=角2,且AB=AC+CD,求证角C=2角B
人气:323 ℃ 时间:2019-08-18 10:10:47
解答
∠1=∠2是不是就是AD是∠BAC的角平分线啊证明:在AB上取点E,是AC = AE.连结ED∵AE = AC,∠1 = ∠2,AD = AD∴△AED≌△ACD∴CD = ED,∠C = ∠AED∵AB = AC+CD = AE + EB∴CD = BE∴ED = BE∴∠B = ∠EDB∵∠AED = ∠B...
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