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已知abc=1,求证:a/(ab+a+1)+b/(bc+a+1)+c/(ca+c+1)=1
人气:437 ℃ 时间:2020-04-07 20:09:30
解答
题目写错了吧,应该是b/(bc+b+1)啊证明:因为abc=1所以b=1/acab=1/cbc=1/a所以a/(ab+a+1)+b/(bc+b+1)+c/(ca+c+1)=a/(1/c+a+1)+(1/ac)/(1/a+1/ac+1)+c/(ac+c+1)=ac/(ac+c+1)+1/(ac+c+1)+c/(ac+c+1)=(ac+c+1)/(ac+c+1)=...
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