若x大于0,y大于0且2x+8y-xy=0求x+y的最小值
人气:315 ℃ 时间:2019-09-17 22:03:20
解答
2x+8y=xy
2/y+8/x=1
x+y=(x+y)*1
=(x+y)(2/y+8/x)
=2x/y+8y/x+2+8
x>0,y>0
2x/y+8y/x>=2√(2x/y*8y/x)=8
所以x+y最小值=8+2+8=18
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