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化简:2sin^2(19/4π)+tan^2(37/4π)*cot(-9/4π)
人气:244 ℃ 时间:2020-09-25 14:16:46
解答
原式=2sin^2(3/4π)+tan^2(5/4π)*cot(-1/4π)
=2sin^2(3/4π)+tan^2(5/4π)*cot(-1/4π)
=2*(1/2)+tan^2(1/4π)*cot(-1/4π)
=1+1*(-1)
=1-1
=0
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