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数学
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若3x^3-x=1,求9x^4+12x^3-3x^2-7x+2003的值,
人气:391 ℃ 时间:2020-01-30 11:38:25
解答
9x^4+12x^3-3x^2-7x+2003
=9x^4-3x^2+12x^3-7x+2003
=3x(3x^3-x)+12x^3-7x+2003
=3x+12x^3-7x+2003
=12x^3-4x+2003
=4(3x^3-x)+2003
=2007
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