∵y=ax/(x²+2)；当x=0时,y=0；当x≠0时,有y=a/(x+2/x).①x＜0时,-x＞0,-x - 2/x≥2√2 ,x+2/x≤ -2√2；a>0时,函数有最小值.y=ax/(x²+2)=a/(x+2/x) ≥-a/(2√2) 结合已知条件ymin=-(√2)/4可知,当x＜0,a=1...