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函数y=2sin(x/3+π/3)[x属于(-π,-π/2)]的值域
人气:364 ℃ 时间:2020-04-16 19:26:02
解答
x∈(-π,-π/2)
x/3∈(-π/3,-π/6)
x/3+π/3∈(0,π/6)
y∈(0,1/2)答案好像是(0,1)x/3+π/3∈(0,π/6) sin(x/3+π/3)∈(0,1/2) 2sin(x/3+π/3)∈(0,1)
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