在锐角三角形ABC中,若角C＝2*角B,则边c/b的范围是?
c/(sin(角C))=b/(sin(角B))
c/b=(sin(角C))/(sin(角B))=(sin(2*角B))/(sin(角B))
=(2*sin(角B)*cos(角B))/(sin(角B))
=2*cos(角B)