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∫(0到-π)x sin(nx)dx=?
如上,把sin(nx)改为cos(nx)=?5
人气:137 ℃ 时间:2020-07-10 07:32:00
解答
两题都给你做下:
————————————————————————————————————
∫ xsin(nx) dx
= (- 1/n)∫ x d[cos(nx)]
= (- x/n)cos(nx) + (1/n)∫ cos(nx) dx
= (- x/n)cos(nx) + (1/n^2)sin(nx) + C

∫(- π→0) xsin(nx) dx
= (- x/n)cos(nx) + (1/n^2)sin(nx)_(x = 0) - (- x/n)cos(nx) + (1/n^2)sin(nx)_(x = - π)
= (- π/n)cos(nπ)
= - π/n,当n为偶数
= π/n,当n为奇数
————————————————————————————————————
∫ xcos(nx) dx
= (1/n)∫ x d[sin(nx)]
= (x/n)sin(nx) - (1/n)∫ sin(nx) dx
= (x/n)sin(nx) + (1/n^2)cos(nx) + C

∫(- π→0) xcos(nx) dx
= (x/n)sin(nx) + (1/n^2)cos(nx)_(x = 0) - (x/n)sin(nx) + (1/n^2)cos(nx)_(x = - π)
= (1/n^2)[1 - cos(nπ)]
= 0,当n为偶数
= 2/n^2,当n为奇数
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