Sn=3n²－2n,则：当n=1时,a2=S1=1；当n≥2时,an=Sn－S(n－1)=6n－5因n=1也满足,则：an=6n－5bn=3/[an(an＋1)]=3/[(6n－5)(6n＋1)]=(1/2)[1/(6n－5)－1/(6n＋1)]则数列{bn}的前n项和Tn=(1/2)[1/1－1/(6n＋1)]=(3n...