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用取对数的方法求函数f(x)=x(x+1)……(x+99)(x+100)求f(0)的导数
人气:205 ℃ 时间:2020-02-03 07:16:40
解答
lgf(x)=lgx+lg(x+1)+...lg(x+100)f'(x)/f(x)=1/x+1/(x+1)+..+1/(x+100)f'(x)=f(x)[1/x+1/(x+1)+...+1/(x+100)] =(x+1)...(x+100)+f(x)[1/(x+1)+..+1/(x+100)]f'(0)=100!+0=100!
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