z=cosθ+isinθ θ∈[0,π],w=-1+i|z-w|=|（cosθ+1）+(sinθ-1)i|=√[（cosθ+1）^2+(sinθ-1)^2]=√[3+2cosθ-2sinθ]=√[3-2√2sin(θ-π/4)]θ-π/4∈[-π/4,3π/4],所以 sin(θ-π/4)∈[-√2/2,1]所以 |z-w|∈[...