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数学
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已知函数f(x)=x三方+3ax平方+3(a+2)x+1既有极大值又有极小值,则实数a的取值范围是
人气:474 ℃ 时间:2019-08-19 12:00:56
解答
f′(x)=3x²+6ax+3(a+2)
因为既有极大值,又有极小值,
则f'(x)=0有两个不同的实数根
所以f′(x)中应△>0
所以:36a²-36(a+2)>0
a²-a-2>0
解得:a2
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