a1=3分之一,a2=15分之1,a3=35分之1,求a1+a2+a3+...+a100的值
人气:113 ℃ 时间:2020-06-20 22:47:55
解答
由题意,得a1=1/(1*3)=1/2*(1-1/3)a2=1/(3*5)=1/2*(1/3-1/5)^a100=1/2*(1/(2n-1)-1/2n+1))所以a1+a2+a3+...+a100=1/2*(1-1/3+1/3-1/5+^+1/(2n-1)-1/(2n+1)))=1/2*(1-1/(2n+1))...
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