a^2+b^2-8b-10a+41=(a-5)^2+(b-4)^2=0
a=5,b=4
1为什么a-5，b-4？a^2+b^2-8b-10a+41=(a^2-10a+25)+(b^2-8b+16)=(a-5)^2+(b-4)^2不过c是最大边的话,5<=c<9,wzhq777的答案是对的