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用因式分解法解方程 (1) (x-1)²-2(x-1)=0
(2) (x+2)²-9=0
(3) 9(x-2)²=4(x+1)²
(4) 2(t-1)²+t=1
人气:248 ℃ 时间:2020-05-13 09:24:59
解答
1.(x-1)(x-1-2)=0x=1或32.(x+2+3)(x+2-3)=0x=-5或13.9(x-2)²-4(x+1)²=0[3(x-2)+2(x+1)][3(x-2)-2(x+1)=0(5x-4)(x-8)=0x=4/5或84.2(t-1)²+t-1=0(t-1)[2(t-1)+1]=0(t-1)(2t-1)=0t=1或1/2
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