首先证∠BDA=90°+1/2∠BCA延长CD交AB于P,两个外角易证∠BDA=1/2∠BAC+1/2∠ABC+∠BCA=1/2(180°-∠BCA)+∠BCA=90+1/2∠BCA设∠BDE=α,则2α=90+1/2∠BCA,α=45+1/4∠BCA最小整数值为46（∠BCA大于0）同理易证∠BFE=...