弧长为C=1800和弦到弧顶的距离为H=275,求圆心角A是多少弧度?
弧半径为R.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=1400
R1=1423.6
R2=1424.38
R3=1424.38
R=1424.38
A=C/R
=1800/1424.38
=1.26371弧度