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方程x² -3x-2=0有2根X1,X2,求x1³ -x2³
人气:289 ℃ 时间:2020-02-04 03:02:13
解答
x²-3x-2=0
x1+x2=3,x1x2=-2
x²=3x+2
x1²=3x1+2,x2²=3x2+2
x1³-x2³=x1*x1²-x2*x2²=x1(3x1+2)-x2(3x2+2)
=3(x1²+x2²)+2(x1+x2)
=3[(x1+x2)²-2x1x2]+2(x1+x2)
=3(9+4)+6=45
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