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求证1+2sinxcosx/cos平方x-sin平方x=1+tanx/1-tamx
人气:298 ℃ 时间:2019-11-19 04:46:53
解答
(1+2sinxcosx)/(cos^2x-sin^2x)
=(cos^2x+sin^2x+2sinxcosx)/(cos^2x-sin^2x) (上下同除以cos^2x)
=(1+tan^2x+2tanx)/(1-tan^2x)
=(1+tanx)^2/([(1-tanx)(1+tanx)]
=(1+tanx)/(1-tanx)
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